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13.1 Continous mode
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In case of gear machininig by continous mode, the milling tool
runs along teeth profile, from tip circle down to diameter that
it is necessary to warrant.
For usual teeth dimensions the lenght of this path is about
2 - 2,2 x normal module.
In case it is possible to fit Feed value along X in order to have
constant feed value along the profile, (
(fig.15A)
(fig.16A)
) according to:
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[15] FEED (X) = FEED profile * Rb / X current
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thus:
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[16] FEED (X) = FEED profile * KFeed with KFEED = Rb / X
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active maching time for a path-lenght s= 2,2 * module
may be calculated by:
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[17] Tunit = s / Frel = 2,20 * mn / Frel
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and for the whole gear, consisting in Z teeth cut in L/p levels:
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[18] Ttotal = Tunit * z * L / p = 2,2 * mn * Z * L / (p * Frel)
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In case feed on profile Frel = 150 mm/nin and p = 50 mm will be:
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[19] Ttotal = Tunit * z * (L / 50) = mn * z * L / 3409
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For example, with (Frel=150 p=50) mn=30 z=28 L=500 will lead to 123'
= 2,05 h for each flank , thus 4,10 h for whole facewidth, that
might reduce to about 2,50 in case of double tool.
By using an HM insert hob diam 360 mm , with cutting parameters:
Vt=110 n=97 a=1,25 L=500+250=750 we have about 173'=2,90 h for
whole facewidth.
This may seem a good result, but if you consider all remaining
service activities (handling, insert change, offset, controls etc)
and the cost of tool and inserts, I think to may say that milling
is anyway a convenient way of machining.
Don't forget that 1 only milling cut may remove much more material
stock than a HM skyving unit action.
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