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PER IL TESTO ITALIANO FATE CLIC su ITALIANO
FOR THE ITALIAN TEXT CLIC ABOVE ITALIANO
FORMULAS, SPECIFIC WEIGHT, COSTS AND OTHER USEFUL INFORMATIONS
1. GIVEN THE WEIGHT OF AN OBJECT IN BRASS (BRONZE AND COPPER) Is DESIRED
KNOW AS IT WILL WEIGHt IN SILVER.
The difference in percent of the specific weight of the copper and it of the silver is of the 17% in favor of this.
SOLUTION : REACH THE 17% OF THE WEIGHT OF THE OBJECT.
Example: WEIGHT of the g OBJECT 28 x 17: 100= 32.76 (weight of the object that will have in silver).
SPECIFIC WEIGHT
2. SPECIFIC WEIGHT OF THE COPPER 8,92- FUSION TO 1083 C°
3. SPECIFIC WEIGHT OF THE SILVER 10, 42- 10,5- FUSION to 960.5 C°
4. SPECIFIC WEIGHT of the GOLD 19,32- FUSION to 1064.4 C°
5. SPECIFIC WEIGHT of the PLATINUM 21,45- FUSION to 1772 C°
6. SPECIFIC WEIGHT of the PALLADIO 12,02- FUSION to 1554 C°
7. KARATO= (equal) 1/ 5 Of GRAM= (equal) To 2 DECIGRAMMES THAT IS 0.2 g
---1(one) DECIGRAMME (dg) = (equal) 0.1 (a tenth of gram).
FOR SILVER AND GOLD
Pure=Pure metal
8. TO GET THE WEIGHT BOTAINED AFTER HAVING DONE THE ALLOY.
WEIGHT of the pure X 1,25= WEIGHT Alloy.
Ex: 500 g (pure) X 1,25= 625g (total weight of the alloy).
OR the WEIGHT of her SEPARATED Alloy for the pure.
ES : 500g (pure) x 0,800 = 625g (total weight of the alloy).
9. TO KNOW THE CONTENT OF PURE IN A ALLOY
Alloy X TITLED = PURE
ES : 625g (alloy) x 0,800 (titled) = 500g (pure)
10. TO KNOW COMMON METAL YOU NEED
TO ADD IN ORDER TO HAVE A ALLOY WITH THE PRECIOUS METAL.
PURE x 0,25 = COMMON METAL
ES : 500g (pure) x 0,25 = 125g (metal common that is added to the pure;
you have: 500g (pure) + 125g (quantity of common metal derived from the preceding operation) = 625g (total weight of her
alloy).
11. FOR KNOW THE WEIGHT OF THE PURE METAL CONTAINED IN A ALLOY
WEIGHT OF ALLOY X TITLED = WEIGHT OF THE PURE (PURE METAL)
L x T =P
Es: (alloy) 1000g x 0,800 (titled) = 800g (pure metal)
Es : (alloy) 500g x 0,800 (titled) = 400g (pure metal)
12. To CALCULATE the TITLE in THOUSANDTH of an INGOT that CONTAINS a KNOWN
QUANTITY of PURE.
DIVIDE THE PURE FOR THE TOTAL WEIGHT OF ITS ALLOY AND IT MULTIPLIES FOR
THOUSAND.
T = F : P x 1000 . (T=TITLE; F=PURE; P=TOTAL WEIGHT).
Ex:(Title = 400g Pure): 500g total weight) x 1000 = 800(title).
13. CALCULATION OF THE WEIGHT OF A ALLOY FOR HAVE A CERTAIN CONTAINED OF PURE.
Ex : a jeweler has received of the pure metal and returns it in alloy
From GOLD at 0,750 (title) as it must take some for have you 325 g of gold pure?
solution : PURE : TITLE = ALLOY
g 325 (PURE metal received) : 0,750 (title) = g 433,2 (metal to give back alloyied)
or multiply the quantity of pure metal for x 1,333 - 325 x 1,333 = 433,2
14. - To REDUCE the TITLE of a alloy from 925 to 750
From the Alloy 750 g - 0 (grams) = 750g
From 925 -750 = 175 (of common metal to add at the alloy to title 925).
15. - To INCREASE the TITLE of a ALLOY, for instance from 550 to 800
Weight of the alloy g1000 - 800 = g 200
Pure metal at 1000 g 800 - 550 = g 250
FIND the WEIGHT for ADDING at the PURE
to PREPARE a ALLOY to 750
multiply the weight of the pure for 0.333 or 0.33 e
the weight of the common metal is gotten and after added it at the pure metal for get
a alloy to 750
OR DIVIDE the WEIGHT of the UNTIL for 3
Ex : 100 g of pure metal more g 33,3 of copper (100 x 0,333=33,3)
In other words, with 100g of pure gold at 1000, with the addition of 33.3 g of
copper, you have gotten 133.3 of pure gold at 750.
COSTS (to which it has added the IVA for the self BILL)
1. To GET the WEIGHT of him SILVER from the WEIGHT of the WAX MULTIPLY
the WEIGHT of the EXAMPLE in WAX for 9,73
EXAMPLE: WEIGHT of the WAX g 1,630 x 9,73 = g 15,850.
2. To OBTAIN the WEIGHT Of the GOLD From the WEIGHT Of the WAX MULTIPLY
For 19,46- Such results are approximate.
3. DECREASE of FUSION for the SILVER 2% (TWO per cent)^c.
4. DECREASE of FUSION for The GOLD 2% (TWO per cent).^c
5. DECREASE of WORKMANSHIP Of the GOLD From the 10% at 16% or 20% it DEPENDS
ON the TYPE of WORKMANSHIP.
6. To CALCULATE the REAL WEIGHT Of the PRECIOUS METAL It is NEEDS
MULTIPLY, the WEIGHT Of the SILVER, to WHICH you NEED, for TWOand ADD
the 14% in WEIGHT (EQUAL to the DECREASE WORKMANSHIP More the DECREASE of FUSION).
BEYOND it to that will BE added ALSO a quantity for the feed head of fusion. THIS quantity will have given back.
7. PRICE to the GRAM for the FUSION of the £...for SILVER more IVA.
8. PRICE of FUSION for the GOLD £ ..... for GRAM more IVA.
9. WEIGHT of the LOOM of a STONE in small plate: g 9 in SILVER.
10. WEIGHT in SILVER of the FOUR PIECES that CONSTITUTE the NECKLACE
GRAMS 24/27
11. For GET the COST of a certain quantity of indicate METAL in
GRAMS:
DIVIDE the PRICE for 1000. And MULTIPLY the QUOTIENT for the GRAMS.
P : 1000 x G
P=Price
G=Grams
For istance: Price L.6000 : 1000 = 6 - Grams 350 x 6 = L. 2100