Metodo iterativo applicato alla funzione:
 f = (0.5)*x + 4
 
delta = 0.4000000000E+01 x = 0.4000000000E+01 f(x) = 0.6000000000E+01
delta = 0.2000000000E+01 x = 0.6000000000E+01 f(x) = 0.7000000000E+01
delta = 0.1000000000E+01 x = 0.7000000000E+01 f(x) = 0.7500000000E+01
delta = 0.5000000000E+00 x = 0.7500000000E+01 f(x) = 0.7750000000E+01
delta = 0.2500000000E+00 x = 0.7750000000E+01 f(x) = 0.7875000000E+01
delta = 0.1250000000E+00 x = 0.7875000000E+01 f(x) = 0.7937500000E+01
delta = 0.6250000000E-01 x = 0.7937500000E+01 f(x) = 0.7968750000E+01
delta = 0.3125000000E-01 x = 0.7968750000E+01 f(x) = 0.7984375000E+01
delta = 0.1562500000E-01 x = 0.7984375000E+01 f(x) = 0.7992187500E+01
delta = 0.7812500000E-02 x = 0.7992187500E+01 f(x) = 0.7996093750E+01
delta = 0.3906250000E-02 x = 0.7996093750E+01 f(x) = 0.7998046875E+01
delta = 0.1953125000E-02 x = 0.7998046875E+01 f(x) = 0.7999023438E+01
delta = 0.9765625000E-03 x = 0.7999023438E+01 f(x) = 0.7999511719E+01
delta = 0.4882812500E-03 x = 0.7999511719E+01 f(x) = 0.7999755859E+01
delta = 0.2441406250E-03 x = 0.7999755859E+01 f(x) = 0.7999877930E+01
delta = 0.1220703125E-03 x = 0.7999877930E+01 f(x) = 0.7999938965E+01
delta = 0.6103515625E-04 x = 0.7999938965E+01 f(x) = 0.7999969482E+01
delta = 0.3051757812E-04 x = 0.7999969482E+01 f(x) = 0.7999984741E+01
delta = 0.1525878906E-04 x = 0.7999984741E+01 f(x) = 0.7999992371E+01
delta = 0.7629394531E-05 x = 0.7999992371E+01 f(x) = 0.7999996185E+01
delta = 0.3814697266E-05 x = 0.7999996185E+01 f(x) = 0.7999998093E+01
delta = 0.1907348633E-05 x = 0.7999998093E+01 f(x) = 0.7999999046E+01
delta = 0.9536743164E-06 x = 0.7999999046E+01 f(x) = 0.7999999523E+01
delta = 0.4768371582E-06 x = 0.7999999523E+01 f(x) = 0.8000000000E+01
delta = 0.4768371582E-06 x = 0.8000000000E+01 f(x) = 0.8000000000E+01
delta = 0.0000000000E+00 x = 0.8000000000E+01 f(x) = 0.8000000000E+01
delta = 0.0000000000E+00 x = 0.8000000000E+01 f(x) = 0.8000000000E+01